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MHT CET20227 Aug 2022Morning ShiftMathematicsPair of LinesActual

The joint equation of two lines passing through the origin and perpendicular to the lines given by 2 x^2+5 x y+3 y^2=0 is

Options

  1. A3 x^2+5 x y+2 y^2=0
  2. B3 x^2-5 x y+2 y^2=0
  3. C3 x^2-5 x y-2 y^2=0
  4. D2 x^2-5 x y+3 y^2=0

Correct answer

B. 3 x^2-5 x y+2 y^2=0

Step-by-step solution

2 x^2+5 x y+3 y^2=0 (x+y)(2 x+3 y)=0 lines are x+y=0 and 2 x+3 y=0 so, perpendicular lines are x-y=0 and 3 x-2 y=0 joint equation (x-y)(3 x-2 y)=0 3 x^2-5 x y+2 y^2=0

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