MHT CET20225 Aug 2022Evening ShiftMathematicsPair of LinesActual
The joint equation of pair of lines which bisects the angle between the lines x^2+3 x y+2 y^2=0 is
Options
- A3 x^2-r 4 e g h 2 x y-3 y^2=0
- B3 x^2+2 x y-3 y^2=0
- C2 x^2-3 x y-2 y^2=0
- D2 x^2+3 x y-2 y^2=0
Correct answer
B. 3 x^2+2 x y-3 y^2=0
Step-by-step solution
Equation of angle bisector of ax ^2+2 hxy + by ^2=0 is given by aligned & x-y a-b = x y h & x^2-y^2 1-2 = x y 3 2 & -3 x^2+3 y^2=2 x y & 3 x^2+2 x y-3 y^2=0 aligned