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MHT CET202120 Sep 2021Morning ShiftMathematicsPair of LinesActual

The joint equation of the pair of lines through the origin and making an equilateral triangle with the line x=3 is

Options

  1. A3 x^2-y^2=0
  2. B3 x^2-2 x y+y^2=0
  3. Cx^2-3 y^2=0
  4. Dx^2+2 x y- 3 x^2=0

Correct answer

C. x^2-3 y^2=0

Step-by-step solution

Slope of line OA = 30^ = 1 3 and Slope of line OB = (-30^ )= -1 3 Equation of OA is y = 1 3 x and equation of OB is y = 1 3 x Hence required equation is (x- 3 y )(x+ 3 y )=0 i.e. x^2-3 y^2=0

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