MHT CET202014 Oct 2020Evening ShiftMathematicsPair of LinesActual
The joint equation of pair of lines passing through (2,3) and parallel to the line =0
Options
- Ax²-y²-4 x+6 y-5=0
- Bx²-y²-4 x+6 y=0
- Cx²-y²-4 x+6 y+17=0
- Dx²-y²-4 x+6 y+2=0
Correct answer
A. x²-y²-4 x+6 y-5=0
Step-by-step solution
x²-y²=0 (x-y)(x+y)=0 Thus slopes of given lines are 1 and -1 . The eq. of lines passing through (2,3) and parallel to given liens are (y-3)=(x-2) and (y-3)=-(x-2) i.e. x-y+1=0 and (x+y-5)=0 Hence required eq. is (x-y+1)(x+y-5)=0x²-x y+x+x y-y²+y-5 x+5 y-5=0x²-y²-4 x+6 y-5=0