The joint equation of pair of lines passing through point of intersection of lines 2 x²-x y-15 y²-7 x+32 y-9=0 and parallel to co-ordinate axes is

Step-by-step solution

Let =2 x²-x y-15 y²-7 x+32 y-9=0 ...(1) d d x =4 x-y-7=0 4 x-y-7=0 ...(2) d d y =-x-30 y+32=0 x+30 y-32=0 ...(3) Solving equation (2) &(3) we get x=2, y=1 (2,1) is the point of intersection of given lines. Lines passing through (2,1) and parallel to co-ordinate axes are x=2 and y=1 . Hence required equation is (x-2)(y-1)=0 x y-2 y-x+2=0 Note : Point of intersection can also be calculated as follows : 2 x²-x y-15 y²-7 x+32 y-9=0 gives a=2, h= -1 2 , b=-15, g= -7 2 , f=16, c=-9 aligned Point of intersection &= ( bg -