MHT CET2010MathematicsPair of Lines
The equation of the lines passing through the origin and having slopes 3 and - 1 3 , is
Options
- A3 y²+8 x y-3 x²=0
- B3 x²+8 x y+3 y²=0
- C3 y²-8 x y-3 x²=0
- D3 x²+8 x y-3 y²=0
Correct answer
D. 3 x²+8 x y-3 y²=0
Step-by-step solution
Here, m₁=3, m₂= -1 3 Hence, the lines are y=3 x, y= -1 3 x On multiplying both the lines, we get (y-3 x)(3 y+x)=0 3 x²+8 x y-3 y²=0