MHT CET2007MathematicsPair of Lines
If x²-2 p x y-y²=0 and x²-2 q x y-y²=0 bisect angles between each other, then
Options
- Ap+q=1
- Bp q=1
- Cp q+1=0
- Dp²+p q+q²=0
Correct answer
C. p q+1=0
Step-by-step solution
The equation of the bisectors of the angles between the lines x²-2 p x y-y²=0 is aligned & x²-y² 1-(-1) = x y -p & x²-y² 2 = -x y p p x²+2 x y-p y²=0 aligned This is same as x²-2 q x y-y²=0 . Therefore p 1 = 2 -2 q =- p -1 p q+1=0