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MHT CET2018MathematicsParabola

The cartesian co-ordinates of the point on the parabola y 2 = − 16 x , whose parameter is 1 2 are

Options

  1. A- 2 , 4
  2. B4 , - 1
  3. C- 1 , - 4
  4. D- 1 , 4

Correct answer

D. - 1 , 4

Step-by-step solution

Given t = 1 2 ; y 2 = − 16 x Comparing with standard parabola, y 2 = − 4 a x We get a = 4 P ( t ) = ( − a t 2 , 2 a t ) = ( − 4 × 1 4 , 2 ( 1 2 4 ) ) P ( t ) = ( − 1 , 4 )

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