Consider a group of 5 boys and 7 girls. The number of different teams, consisting of 2 boys and 3 girls that can be formed from this group if there are two specific girls A and B , who refuse to be the members of the same team, is

Step-by-step solution

There are 5 boys and 7 girls in a class. Total number of ways = ^5 C ₂ ^7 C ₃=350 If both girls A and B are in the same team, then ^5 C ₁ ^5 C ₂=50 Required number of ways = Total number of ways - Both girls A and B are in the same team =350-50=300