Five students are to be arranged on a platform such that the boy B₁ occupies the second position and such that the girl G ₁ is always adjacent to the girl G₂ . Then, the number of such possible arrangements is

Step-by-step solution

There are 5 positions. Given that B ₁ occupies 2^ nd position B ₁ can be arranged in 1 way. As G ₁ and G ₂ are always together, none of them can take 1^ st position. G ₁, G ₂ and one of the remaining students can be arranged on 3^ rd , 4^ th and 5^ th position when G ₁ and G ₂ are always together in 2 ! 2 ! Ways. And remaining 2 students can be arranged in 2 ! Ways. The required number of arrangements =2 ! 2 ! 2 !=8