The probability that a bomb will hit the target is 0.8 . Out of 6 bombs dropped, probability that at least 1 will miss the target is...

Step-by-step solution

Probability of a bomb hitting the target, p = 0.8 = 4 5 Probability of a bomb missing the target, q = 1 - p = 0.2 = 1 5 Total number of bombs dropped, n = 6 The probability that at least one bomb misses the target is 1 - P( no bomb misses the target ) P( no bomb misses the target ) = P( all 6 bombs hit the target ) = p^6 = ( 4 5 )^6 Required probability = 1 - ( 4 5 )^6 Answer: 1 - ( 4 5 )^6