MHT CET202613 April 2026Morning ShiftMathematicsProbabilityActual
A random variable X has the following probability distribution X = x 1 2 3 4 5 6 7 8 P(X=x) 0.15 0.23 0.10 0.12 0.20 0.08 0.07 0.05 For the events E = X is a prime number , F = X < 4 , P(E F) is
Options
- A0.5
- B0.77
- C0.35
- D0.75
Correct answer
D. 0.75
Step-by-step solution
The event E is that X is a prime number. From the given values of X , the prime numbers are 2, 3, 5, 7 . E = 2, 3, 5, 7 The event F is that X F = 1, 2, 3 The union of events E and F is: E F = 1, 2, 3, 5, 7 The probability P(E F) is the sum of the probabilities of these individual outcomes: P(E F) = P(X=1) + P(X=2) + P(X=3) + P(X=5) + P(X=7) Substituting the given probabilities: P(E F) = 0.15 + 0.23 + 0.10 + 0.20 + 0.07 = 0.75 Answer: 0.75