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AP EAMCET2005MathematicsApplication of Derivatives

A stone thrown upwards, has its equation of motion s=490 t-4.9 t^2 . Then the maximum height reached by it, is

Options

  1. A24500
  2. B12500
  3. C12250
  4. D25400

Correct answer

C. 12250

Step-by-step solution

Given that s=490 t-4.9 t^2 On differentiating w.r.t. t , we get d s d t =490-9.8 t A stone is reached the maximum height, when d s d t =0 array cc & 490-9.8 t=0 & t= 490 9.8 = 100 2 =50 array Maximum height at t=50 aligned s & =490(50)-4.9(50)^2 & =24500-12250 & =12250 aligned

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