MHT CET202525 Apr 2025Evening ShiftMathematicsProbabilityActual
A player tosses two coins. He wins Rs. 10, if 2 heads appears, Rs. 5, if one head appear and Rs. 2 if no head appears. Then variance of winning amount is
Options
- A38.5
- B5.5
- C8.25
- D44.00
Correct answer
C. 8.25
Step-by-step solution
Expected value and variance for the two-coin toss game In a game where two fair coins are tossed, the possible outcomes are HH , HT , TH , and TT , each with probability 1 4 . The winning amount X is 10 for HH ( P(X=10)=1/4 ), 5 for HT or TH ( P(X=5)=1/2 ), and 2 for TT ( P(X=2)=1/4 ). The expected value is E(X) = x P(X=x) = 10 1 4 + 5 1 2 + 2 1 4 = 5.5 . E(X^2) = 100 1 4 + 25 1 2 + 4 1 4 = 38.5 . Variance is Var (X) = E(X^2) - [E(X)]^2 = 38.5 - (5.5)^2 = 8.25 . Hence, the variance is C .