AP EAMCET2005MathematicsApplication of Derivatives
The radius of a circular plate is increasing at the rate of 0.01 ~cm / s when the radius is 12 ~cm . Then, the rate at which the area increases, is
Options
- A0.24 sq cm / s
- B60 sq cm / s
- C24 sq cm / s
- D1.2 sq cm / s
Correct answer
A. 0.24 sq cm / s
Step-by-step solution
The area of circular plate is A= r^2 On differentiating w.r.t. t , we get aligned & d A d t =2 r d r d t & d A d t =2 (12)(0.01) & [ given d r d t =0.01 r=12 ] & d A d t = 0.24 sq cm / sec aligned