MHT CET202522 Apr 2025Morning ShiftMathematicsProbabilityActual
The p.d.f. of a continuous random variable X is f (x)= array cc x^2 18 & if -3 < x < 3 0 & otherwise array . Then P [| X | < 2]=
Options
- A1 27
- B2 13
- C8 27
- D4 27
Correct answer
C. 8 27
Step-by-step solution
The probability density function is defined by f (x) = cases x^2 18 & if -3 Since |X| P [|X| Integrating yields 1 18 [ x^3 3 ]_ -2 ² = 1 18 ( 8 3 - -8 3 ) = 1 18 16 3 = 16 54 = 8 27 . This corresponds to option C .