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MHT CET202415 May 2024Morning ShiftMathematicsProbabilityActual

A random variable X has the following probability distribution Then p (x 2) is equal to

Options

  1. A35 36
  2. B34 36
  3. C33 36
  4. D31 36

Correct answer

A. 35 36

Step-by-step solution

aligned & Since _ x=1 ^5 P ( X =x)=1 & k ^2+2 k + k +2 k +5 k ^2=1 & 6 k ^2+5 k -1=0 & ( k +1)(6 k -1)=0 & k = 1 6 [ k 0] aligned aligned & P ( X 2)= P ( X =2)+ P ( X =3)+ P ( X =4) &+ P ( X =5) aligned aligned & = 2 6 + 1 6 + 2 6 + 5 36 & = 12+6+12+5 36 & = 35 36 aligned

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