MHT CET202411 May 2024Evening ShiftMathematicsProbabilityActual
A random variable X has the following probability distribution For the event E= X is a prime number , F= X 4 , then P(E F) is
Options
- A0.5
- B0.77
- C0.35
- D0.75
Correct answer
D. 0.75
Step-by-step solution
aligned P ( E ) & = P ( X is a prime number ) & = P ( X =2 or X =3 or X =5 or X =7) & = P ( X =2)+ P ( X =3)+ P ( X =5) & + P ( X =7) & =0.23+0.10+0.20+0.07 & =0.6 aligned aligned P ( F ) & = P ( X 4) & = P ( X =1)+ P ( X =2)+ P ( X =3) & =0.15+0.23+0.10 & =0.48 P ( E F ) & = P ( X is a prime number less than 4) & = P ( X =2)+ P ( X =3) & =0.23+0.10 & =0.33 P ( E F ) & = P ( E )+ P ( F )- P ( E F ) & =0.6+0.48-0.33 & =0.75 aligned