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MHT CET202410 May 2024Morning ShiftMathematicsProbabilityActual

A random variable x has the following probability distribution For the events E = X is prime number F= X 4 Then P(E F)=

Options

  1. A0.87
  2. B0.35
  3. C0.77
  4. D0.50

Correct answer

C. 0.77

Step-by-step solution

aligned & P ( E )= P ( X =2 or X =3 or X =5 or X =7) &= P ( X =2)+ P ( X =3)+ P ( X =5)+ P ( X =7) &=0.23+0.12+0.20+0.07=0.62 & P ( F )= P ( X 4) &= P ( X =1)+ P ( X =2)+ P ( X =3) &=0.15+0.23+0.12=0.50 & P ( E F ) &= P ( X is a prime number less than 4) &= P ( X =2)+ P ( X =3) &=0.23+0.12=0.35 & P ( E F )= P ( E )+ P ( F )- P ( E F ) &=0.62+0.50-0.35=0.77 aligned

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