There are three events A , B , C , one of which must and only one can happen. The odds are 8:3 against A , 5: 2 against B and the odds against C is 43: 17 k , then value of k is

Step-by-step solution

The odds against A are 8: 3 . P ( ~A )= 3 11 Odds against B are 5: 2 array ll & P(B)= 2 7 & P(A)+P(B)+P(C)=1 & 3 11 + 2 7 +P(C)=1 & P(C)=1- 2 7 - 3 11 & P(C)= 34 77 array odds against P ( C )= 77-34 34 = 43 34 But odds against C = 43 17 k aligned & 43 17 k = 43 34 & k=2 aligned