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AP EAMCET2003MathematicsApplication of Derivatives

The minimum value of 2 x^2+x-1 is :

Options

  1. A- 1 4
  2. B3 2
  3. C- 9 8
  4. D9 8

Correct answer

C. - 9 8

Step-by-step solution

Let y=2 x^2+x-1y^ =4 x+1 For maxima or minima, put y^ =0 x=- 1 4 y^ =4=+ ve y is minimum at x=- 1 4 . Thus, minimum value =2 (- 1 4 )^2+ (- 1 4 )-1 2 16 - 1 4 -1= 1 8 - 5 4 =- 9 8

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