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MHT CET20244 May 2024Morning ShiftMathematicsProbabilityActual

A random variable X has the following. -probability distribution Then P ( X 2) is equal to

Options

  1. A7 12
  2. B23 36
  3. C1 36
  4. D1 6

Correct answer

B. 23 36

Step-by-step solution

aligned & k ^2+2 k + k +2 k +5 k ^2=1 & 6 k ^2+5 k =1 & 6 k ^2+5 k -1=0 & 6 k ^2+6 k - k -1=0 & (6 k-1)(k+1)=0 & k= 1 6 [ k=-1 is not possible ] & P(X 2)=1-P(X 2) & =1- ( k ^2+2 k ) & =1- ( 1 36 + 2 6 ) & =1- 13 36 & = 23 36 aligned

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