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MHT CET20244 May 2024Morning ShiftMathematicsProbabilityActual

A multiple choice examination has 5 questions. Each question has three alternative answers of which exactly one is correct. The probability, that a student will get 4 or more correct answers just by guessing, is

Options

  1. A10 3^5
  2. B17 3^5
  3. C13 3^5
  4. D11 3^5

Correct answer

D. 11 3^5

Step-by-step solution

Probability of guessing correct answer be p= 1 3 q = 2 3 Let random variable X denotes the number of correct answers. array ll & X B (5, 1 3 ) & Required probability = P ( X 4) & = P ( X =4)+ P ( X =5) & = ^5 C ₄ ( 1 3 )^4 ( 2 3 )+ ^5 C ₅ ( 1 3 )^5 & =5 2 3^5 + 1 3^5 & = 11 3^5 array

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