Ten bulbs are drawn successively, with replacement, from a lot containing 10 % defective bulbs, then the probability that there is at least one defective bulb, is

Step-by-step solution

Let X : be the number of defective bulbs Possible values of X is 1 . Here, n = number of bulbs picked =10 . Let P (probability of getting defective bulb) aligned & =10 %= 1 10 & q=1-p=1- 1 10 = 9 10 aligned Probability that at least one bulb is defective =1- P (getting 0 defective bulb) =1- P ( X =0)=1- ¹⁰ C ₀( p )^0( q )¹⁰⁻⁰=1-1 1 ( 9 10 )¹⁰=1- ( 9 10 )¹⁰