MHT CET202314 May 2023Evening ShiftMathematicsProbabilityActual
A fair die with numbers 1 to 6 on their faces is thrown. Let X denote the number of factors of the number, on the uppermost face, then the probability distribution of X is
Options
- Aarray |l|c|c|c|c| X =x & 1 & 2 & 3 & 4 P ( X =x) & 1 6 & 1 2 & 1 6 & 1 6 array
- Barray |l|c|c|c|c| X =x & 1 & 2 & 3 & 4 P ( X =x) & 1 6 & 1 6 & 1 6 & 1 2 array
- Carray |l|c|c|c|c| X =x & 1 & 2 & 3 & 4 P ( X =x) & 1 2 & 1 6 & 1 6 & 1 6 array
- Darray |l|c|c|c|c| X =x & 1 & 2 & 3 & 4 P ( X =x) & 1 6 & 1 6 & 1 2 & 1 6 array
Correct answer
A. array |l|c|c|c|c| X =x & 1 & 2 & 3 & 4 P ( X =x) & 1 6 & 1 2 & 1 6 & 1 6 array
Step-by-step solution
S= 1,2,3,4,5,6 The values of X for the possible outcomes of the experiment are as follows: aligned & X(1)=1, X(2)=2, X(3)=2, X(4)=3 & X(5)=2, X(6)=4 & P(X=1)=P[ 1 ]= 1 6 & P(X=2)=P[ 2,3,5 ]= 3 6 = 1 2 & P(X=3)=P[ 4 ]= 1 6 & P(X=4)=P[ 6 ]= 1 6 aligned The probability distribution of X is array |l|c|c|c|c| X =x & 1 & 2 & 3 & 4 P ( X =x) & 1 6 & 1 2 & 1 6 & 1 6 array