An irregular six faced die is thrown and the probability that, in 5 throws it will give 3 even numbers is twice the probability that it will give 2 even numbers. The number of times, in 6804 sets of 5 throws, you expect to give no even number is

Step-by-step solution

Let p be the probability of getting even number. Let random variable X B ( n , p ) Given that P(X=3)=2 P(X=2) ^5 C ₃ p ^3 q ^2=2 ^5 C ₂ p ^2 q ^3 p =2 q p + q =1 p = 2 3 and q = 1 3 P ( X =0)= ^5 C ₀ p ^0 q ^5= 1 3^5 In 1 set of 5 throws, number of times getting no even number is 1 3^5 . In 6804 sets of 5 throws, number of times getting no even number is 1 3^5 6804=28