MHT CET202312 May 2023Morning ShiftMathematicsProbabilityActual
The p.m.f of random variate X is P ( X )= cases 2 x n ( n +1) , & x=1,2,3, , n 0, & otherwise cases Then E(X)=
Options
- An +1 3
- B2 n +1 3
- Cn +2 3
- D2 n -1 3
Correct answer
B. 2 n +1 3
Step-by-step solution
aligned P ( X ) & = array l 2 x n ( n +1) , x=1,2,3, , n 0, othewise array . E ( X ) & = _ i =1 ^ n x_ i p (x_ i ) & = 2 n ( n +1) + 8 n ( n +1) + + 2 n ^2 n ( n +1) & = 2 (1^2+2^2+ + n ^2 ) n ( n +1) & = 2 n ( n +1)(2 n +1) 6 n ( n +1) & = 2 n +1 3 aligned