AP EAMCET2001MathematicsApplication of Derivatives

The equation of tangent to the curve 6 y=7-x^3 at (1,1) is

Options

A2 x+y=3
Bx+2 y=3
Cx+y=-1
Dx+y+2=0

Correct answer

B. x+2 y=3

Step-by-step solution

Given curve is 6 y=7-x^3 On differentiating w.r.t. x , we get aligned 6 y^ & =-3 x^2 y_ (1,1) ^ & =- 3 6 =- 1 2 aligned The equation of the tangent is array rlrl & & y-1 & =- 1 2 (x-1) & & 2 y-2 & =-x+1 & x+2 y & =3 array

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