MHT CET202310 May 2023Evening ShiftMathematicsProbabilityActual
If the sum of mean and variance of a Binomial Distribution is 15 2 for 10 trials, then the variance is
Options
- A1.5
- B2.5
- C4.5
- D3.5
Correct answer
B. 2.5
Step-by-step solution
array ll & Mean + variance = 15 2 & n p+n p q= 15 2 & n p+n p(1-p)= 15 2 [ p+q=1] & n (2 p-p^2 )= 15 2 & 2 p-p^2= 15 2 10 [n=10] & 4 p^2-8 p+3=0 & (2 p-3)(2 p-1)=0 & p= 3 2 or p= 1 2 & p= 1 2 ...[0 < p < 1] & q=1- 1 2 = 1 2 & Variance =n p q=10 1 2 1 2 =2.5 array