A , B , C are three events, one of which must and only one can happen. The odds in favor of A are 4: 6 , the odds against B are 7: 3 . Thus, odds against C are

Step-by-step solution

Odd in favor of A is 4: 6 . P ( A )= 4 10 Odd against B is 7: 3 P ( B )= 3 10 Since only one of the events A, B and C can happen, we get array ll & P ( A )+ P ( B )+ P ( C )=1 & 4 10 + 3 10 + P ( C )=1 & P ( C )= 3 10 & P ( C ^ )= 7 10 array odds against the event C are P ( C ^ ): P ( C ) aligned & = 7 10 : 3 10 & =7: 3 aligned