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MHT CET202211 Aug 2022Morning ShiftMathematicsProbabilityActual

A, B, C are three events, one of which must and only one can happen the odds in favour of A are 4: 6 , odds against B are 7: 3 , then odds against C are

Options

  1. A7:3
  2. B3:7
  3. C6:4
  4. D4:6

Correct answer

A. 7:3

Step-by-step solution

P(A)= 4 4+6 = 2 5 , P(B)= 3 3+7 = 3 10 A, B and C are mutually exclusive and exhaustive aligned & P(A)+P(B)+P(C)=1 & 2 5 + 3 10 +P(C)=1 & P(C)= 3 10 aligned Now, odds against to the event C= 1-P(C) P(C) = 1- 3 10 3 10 = 7 3

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