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MHT CET20228 Aug 2022Evening ShiftMathematicsProbabilityActual

For a Binomial variate x , mean is 2 and variance is 1 , Then odds in favor of X=0 are

Options

  1. A4:1
  2. B15:1
  3. C1:15
  4. D1:4

Correct answer

C. 1:15

Step-by-step solution

Mean =n p=2 , variance =n p q=1 q= 1 2 , p= 1 2 and n=4 Now P(x=0)= ^4 C₀ P^0 q^4=1 1 ( 1 2 )^4= 1 16 odds in favour of p(x=0)= 1 16 1- 1 16 =1: 15

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