MHT CET202124 Sep 2021Evening ShiftMathematicsProbabilityActual
The probability distribution of a random variable X is Then Var ( X )=
Options
- An ^2-1 12
- Bn ^2- n 6
- Cn ^2- n 12
- Dn ^2-1 6
Correct answer
A. n ^2-1 12
Step-by-step solution
aligned p _ i x _ i & = 1 n + 2 n + 3 n + .+ n n & = 1+2+3+ n n = n ( n +1) 2( n ) = n +1 2 aligned aligned & p _ i x _ i ^2= 1 n + 4 n + 9 n + .+ n ^2 n & p _ i x _ i ^2= 1 n + 4 n + 9 n + .+ n ^2 n & = 1+4+9+ n ^2 n = n ( n +1)(2 n +1) 6 n = ( n +1)(2 n +1) 6 & Var ( x )= p _ i x _ i ^2- ( p _ i x _ i )^2 & = ( n +1)(2 n +1) 6 - [ ( n +1) 2 ]^2= 2 n ^2+3 n +1 6 - n ^2+2 n +1 4 & = 4 n ^2+6 n +2-3 n ^2-6 n -3 12 = n ^2-1 12 aligned