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MHT CET202122 Sep 2021Morning ShiftMathematicsProbabilityActual

A random variable X has following distribution array |l|l|l|l|l|l|l| X = x & 1 & 2 & 3 & 4 & 5 & 6 P ( X = x ) & k & 3 k & 5 k & 7 k & 8 k & K array Then P (2 x < 5)=

Options

  1. A7 25
  2. B3 5
  3. C24 25
  4. D23 25

Correct answer

B. 3 5

Step-by-step solution

We have k +3 k +5 k +7 x +8 k + k =1 k = 1 25 P (2 x 5)= 1 25 (3+5+7)= 15 25 = 3 5

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