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MHT CET202120 Sep 2021Morning ShiftMathematicsProbabilityActual

A random variable X has the following probability distribution Then F(4)=

Options

  1. A3 10
  2. B1 10
  3. C7 10
  4. D4 5

Correct answer

D. 4 5

Step-by-step solution

aligned & Here k +2 k +2 k +3 k + k ^2+2 k ^2+7 k ^2+ k =1 & 10 k ^2+9 k -1=0 (10 k -1)( k +1)=0 & k = 1 10 ( k 0) & F (4)= k +2 k +2 k +3 k =8 k = 8 10 = 4 5 aligned

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