MHT CET202015 Oct 2020Evening ShiftMathematicsProbabilityActual
If the p.m.f. is given by P ( X )= k ( array c 4 x array ) , for x=0,1,2,3,4, k >0=0 , otherwise then the value of k is
Options
- A3 16
- B7 16
- C1 16
- D5 16
Correct answer
C. 1 16
Step-by-step solution
For P(X=0)=k ( array l 4 0 array )=k 4 0 =k 1=k P(X=1)=k ( array l 4 1 array )=k 4 1 =k(4)=4 k array l P(X=2)=k ( array l 4 2 array )=k 4 2 =k(6)=6 k P(X=3)=k ( array l 4 3 array )=k x⁴ C₃=k(4)=4 k P(x=4)=k ( array l 4 4 array )=k 4 C₄=(k)(1)=k array Since P(X) is p.m.f. k+4 k+6 k+4 k+k=1 16 k=1 k= 1 16