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MHT CET202013 Oct 2020Evening ShiftMathematicsProbabilityActual

If the p. m. f. of a random variable X is array |c|c|c|c|c|c| X & 1 & 2 & 3 & 4 & 5 P ( X =x) & k & k 3 & k 4 & k 2 & k 2 array then k=

Options

  1. A15 31
  2. B1 12
  3. C11 12
  4. D12 31

Correct answer

D. 12 31

Step-by-step solution

Here k + k 3 + k 4 + k 2 + k 2 =1 k ( 12+4+3+6+6 12 )=1 k ( 31 12 )=1 k = 12 13

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