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MHT CET202012 Oct 2020Evening ShiftMathematicsProbabilityActual

The probability mass function of a random variable X is P(X=x)= 5 2⁵ if x=0,1,2,3,4,5=0 otherwise then, P(X 2)=

Options

  1. AP(X>3)
  2. BP(X 3)
  3. CP(X 2)
  4. DP(X>4)

Correct answer

B. P(X 3)

Step-by-step solution

aligned P ( x 2) &= P ( x =0)+ P ( x =1)+ P ( x =2) &= ⁵ C ₀ 2⁵ + ⁵ C ₁ 2⁵ + ⁵ C ₂ 2⁵ &= 1 2⁵ (1+5+10)= 16 32 P ( x 3) &= P ( x =3)+ P ( x =4)+ P ( x =5) &= ⁵ C ₃ 2⁵ + ⁵ C ₄ 2⁵ + ⁵ C ₅ 2⁵ &= 1 2⁵ (10+5+1)= 16 32 aligned

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