MHT CET20192 May 2019Morning ShiftMathematicsProbabilityActual
A random variable X has following probability distribution X = x 1 2 3 4 5 6 P X = x K 3 K 5 K 7 K 8 K K Then, P 2 ≤ X < 5 = ________
Options
- A3 5
- B7 25
- C23 25
- D24 25
Correct answer
A. 3 5
Step-by-step solution
Given: Probability distribution X = x 1 2 3 4 5 6 P X = x K 3 K 5 K 7 K 8 K K ∵ ∑ 1 = 1 6 p X = x = 1 ⇒ 25 k = 1 ⇒ k = 1 25 then, p 2 ≤ x < 5 = p x = 2 + p x = 3 + p x = 4 = 3 k + 5 k + 7 k = 15 k ⇒ 3 5