MHT CET2019Evening ShiftMathematicsProbabilityActual
If three dices are thrown then the probability that the sum of the numbers on their uppermost faces to be atleast 5 is
Options
- A1 53
- B53 54
- C1 54
- D52 53
Correct answer
B. 53 54
Step-by-step solution
If there dice are drawn, then n ≤ = 6 3 = 216 Let E the sum of the number on their uppermost faces are less than 5 as follows 1,1 , 1 , 1,1 , 2 , 1,2 , 1 , 2,1 , 1 ∴ n E = 4 Now, probability that the sum of the numbers on their uppermost faces to be atleast 5 = 1 - P E 2 = 1 - 4 216 = 1 - 1 54 = 53 54