A coin is tossed three times. If X denotes the absolute difference between the number of heads and the number of tails then P X = 1 =

Step-by-step solution

H H H − 3 H and 0 T H H T − 2 H and 1 T = | n ( H ) − n ( T ) | = 1 H T H − 2 H and 1 T = | n ( H ) − n ( T ) | = 1 H T T − 1 H and 2 T = | n ( H ) − n ( T ) | = 1 T H H − 2 H and 1 T = | n ( H ) − n ( T ) | = 1 T H T − 2 T and 1 H = | n ( H ) − n ( T ) | = 1 T T H − 2 T and 1 H = | n ( H ) − n ( T ) | = 1 T T T − 3 T P ( X = 1 ) = 6 8 = 3 4 Or (second method) Probability distribution of X Out come 3T 2T1H 1T2H 3H X 3 1 1 3 P 1 8 3 8 3 8 1 8 ⇒ P X = 1 = 3 8 + 3 8 = 3 4