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MHT CET2017MathematicsProbability

For the following distribution function F ( x ) of a random variable X x 1 2 3 4 5 6 F(x) 0.2 0.37 0.48 0.62 0.85 1 P 3 < X ≤ 5 =

Options

  1. A0.48
  2. B0.37
  3. C0.27
  4. D1.47

Correct answer

B. 0.37

Step-by-step solution

P 3 < x ≤ 5 = P x = 4 + P ( x = 5 ) = ( F ( 4 ) − F ( 3 ) ) + ( F ( 5 ) − F ( 4 ) ) = 0.14 + 0.23 = 0.37

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