MHT CET2016MathematicsProbability
If random variable X ∼ B n = 5 , p = 1 3 then P 2 < X < 4 =
Options
- A80 243
- B40 243
- C40 343
- D80 343
Correct answer
B. 40 243
Step-by-step solution
Given n = 5 p = 1 3 ∴ q = 2 3 P 2 < x < 4 = P x = 3 = 5 C 3 1 3 3 2 3 2 = 5 × 4 2 × 1 27 × 4 9 = 40 243