Three boxes contain respectively 3 white and 1 black, 2 white and 2 black, 1 white and 3 black balls, from each of the boxes one ball is drawn at random. The probability that 2 white and 1 black balls will be drawn, is

Step-by-step solution

Given, Box ( I )=3 W, 1 B ; Box ( II )=2 W, 2 B ; Box ( III )=1 W, 3 B . Required probability array l =P(B W W)+P(W B W)+P(W W B) =P(B) P(W) P(W)+P(W) P(B) P(W) +P(W) P(W) P(B) = 1 4 2 4 1 4 + 3 4 2 4 1 4 + 3 4 2 4 3 4 = 2+6+18 64 = 26 64 = 13 32 array