MHT CET2009MathematicsProbability
Given P(A B)=0.6, P(A B)=0.2 , the probability of exactly one of the event occurs is
Options
- A0.4
- B0.2
- C0.6
- D0.8
Correct answer
A. 0.4
Step-by-step solution
Given, P(A B)=0.6, P(A B)=0.2 Probability of exactly one of the event occurs is P( A B)+P(A B )=P(B)-P(A B)+P(A)-P(A B)=P(A B)+P(A B)-2 P(A B) [ P(A B)=P(A)+P(B)-P(A B)]=P(A B)-P(A B)=0.6-0.2=0.4