MHT CET202523 Apr 2025Evening ShiftMathematicsProperties of TrianglesActual
In a triangle with one of the angles 120^ , the lengths of the sides form an A.P. If length of the greatest side is 7 m , then the area of the triangle is
Options
- A15 3 4 ~m ^2
- B15 3 2 ~m ^2
- C15 2 ~m ^2
- D15 4 ~m ^2
Correct answer
A. 15 3 4 ~m ^2
Step-by-step solution
Let the triangle sides form an arithmetic progression, represented as x-d , x , and x+d , where x+d = 7 is the greatest side. The 120^ angle is opposite the longest side, designated as angle C . Applying the Law of Cosines: (x+d)^2 = (x-d)^2 + x^2 - 2(x-d)x 120^ Substituting 120^ = - 1 2 and x+d = 7 : 49 = (x-d)^2 + x^2 + x(x-d) 49 = 3x^2 - 3xd + d^2 Expressing d = 7 - x and substituting: 49 = 3x^2 - 3x(7-x) + (7-x)^2 49 = 7x^2 - 35x + 49 0 = 7x(x - 5) Sides must be positive, so x = 5 m, and d = 2 m. The sides are