MHT CET202520 Apr 2025Evening ShiftMathematicsProperties of TrianglesActual
In a triangle ABC , the sides a, ~b , c are such that they are the roots of the equation x^3-11 x^2+38 x-40=0 Then A a + B b + C c =
Options
- A3 4
- B1
- C9 16
- D1 16
Correct answer
C. 9 16
Step-by-step solution
The sides of the triangle are the roots of the equation x^3 - 11x^2 + 38x - 40 = 0 . Testing integer divisors of 40 reveals that x = 2 is a root. Dividing the cubic polynomial by (x - 2) yields x^2 - 9x + 20 , which factors as (x - 4)(x - 5) . The sides are therefore 2 , 4 , and 5 in some order. Using the Law of Cosines, A = b^2 + c^2 - a^2 2bc , with similar expressions for B and C . Substituting into A a + B b + C c gives b^2 + c^2 - a^2 2abc + a^2 + c^2 - b^2 2abc + a^2 + b^2 - c^2 2abc . The sum simplifies to a