Two sides of a triangle are 3 +1 and 3 -1 and the included angle is 60^ , then the difference of the remaining angles is

Step-by-step solution

Let a = 3 +1, ~b = 3 -1, C =60^ Using cosine Rule, aligned & c ^2= a ^2+ b ^2-2 ab C & c ^2=( 3 +1)^2+( 3 -1)^2-2( 3 +1)( 3 -1) 1 2 & c ^2=6 aligned aligned c^2 & =6 c & = 6 aligned Using sine Rule, aligned & a A = b B = c C & Consider & b B = c C & 3 -1 B = 6 3 2 aligned array ll & b B = c C & 3 -1 B = 6 3 2 & B = 3 -1 2 2 & B =15^ & A =105^ array ...[Remaining angle of a Triangle] Difference =90^