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MHT CET20192 May 2019Morning ShiftMathematicsProperties of TrianglesActual

In ∆ A B C ; with usual notations, if cos ⁡ A = sin ⁡ B sin ⁡ C , then, the triangle is ________

Options

  1. Aacute angled triangle
  2. Bequilateral triangle
  3. Cobtuse angled triangle
  4. Dright angled triangle

Correct answer

D. right angled triangle

Step-by-step solution

Given cos ⁡ A = s i n B s i n C b 2 + c 2 - a 2 2 b c = b c ⇒ a 2 + b 2 = c 2 Pythagoras theorem) then ∆ A B C is right angle triangle.

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