MHT CET2019Evening ShiftMathematicsProperties of TrianglesActual

If R is the circum radius of Δ A B C , then A Δ A B C = ….

Options

Aa b c R
Ba b c 4 R
Ca b c 3 R
Da b c 2 R

Correct answer

B. a b c 4 R

Step-by-step solution

In any Δ A B C we know that Area of Δ = 1 2 b c sin ⁡ A ⇒ s i n A = 2 Δ b c …. (i) also, R = a 2 s i n A …. (ii) From Eqs. (i) and (ii), we have R = a 2 2 Δ b c ⇒ R = a b c 4 Δ ⇒ Δ A B C = a b c 4 R

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